FORCE VARIATION AT DIFFERENT PRESSURES IN A BOURDON TUBE “A” FORCE = 9 OZ. PRESSURE = 20 PSIG BOURDON TUBE FORCE = 1 POUND = 16 OZ. PRESSURE = 45 PSIG “C” FORCE = 1 POUND & 15 OZ. = 31 OZ. PRESSURE = 60 PSIG NOTE: The 31 OZ. force of “C” can be attained by increasing the fluid supply pressure, as illustrated, to 60 PSIG, or if Pascal’s Law is true, by isolating the Bourdon tube from the pressure source and applying the one pound (16 OZ.) force of “B” to 1/60th IN² of the incompressible fluid surface of “C”, causing a 60 PSIG the pressure reading. If Work = Force X Distance (W=FD) and (“D” FOR “B”) = (“D” FOR “C”); then W ”B” = 16 units and W ”C” = 31 units; however W ”B” can generate W ”C”, as explained; therefore, “B” can attain 193.75% (31 OZ/16 OZ) more W if its force is applied to the fluid surface of the incompressible fluid surface of “C”. Conclusion: Lesser Winput can produce greater Woutput. 12.219 "B"
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